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CGP EDU Academic Team
Published on: August 14, 2026
If H 2 + 1/2 O 2 ⎯→ H 2 O, Δ H = – 68 kcal
K + H 2 O + water ⎯→ KOH (aq) + 1/2 H 2 , Δ H = – 48 kcal
KOH + water ⎯→ KOH (aq), Δ H = – 14 kcal
Find the heat of formation of KOH.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(–102 kcal)
K(s) + 
O 2 (g) + 
H 2 (g) ⎯→ KOH Δ H = ?
H 2 + 
O 2 ⎯→ H 2 O Δ H = – 68 kcal ...(i)
K + H 2 O ⎯→ KOH(aq.) + 
H 2 (g) Δ H = – 48 kcal ...(ii)
KOH + water ( ty ) ⎯→ KOH(aq.) Δ H = – 14 kcal ...(iii)
Δ H f,KOH = (i) + (ii) – (iii) Δ H f,KOH = – 48 – 68 – (–14) = –102 kcal.
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